![2(x+3)^2-10\\=2[(x+3)^2-5]\\=2[(x+3)^2-(\sqrt{5})^2]\\\\=2[(x+3+\sqrt{5})(x+3-\sqrt{5})]](/tpl/images/0711/5406/3c4ba.png)
How do you factorise this using DOPS/DOTS?
2(x + 3)^2-10...
Answers: 1
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