A smartphone company found in a survey that 6% of people did not own a smartphone, 15% owned a smartphone only, 26% owned a smartphone and only a tablet, 32% owned a smartphone and only a computer, and 21% owned all three. If a person were selected at random, what is the probability that the person would own a smartphone only or a smartphone and computer

47%

Step-by-step explanation:

we are required to find the probability to randomly select from the union of those who own a smartphone only and those who own a smartphone and computer.

an addition of the subsets cover the entire set.

6 + 15 + 26 + 32 + 21 = 100%

let

p(A)= probability of smartphone only

p(B) = probability of smartphone and computer

p(A U B) = P(A) + P(B)

= 15% + 32%

= 47%

answer is : muchas/tipicas

have a nice day!

~recklesschicken

50x5=$250

step-by-step explanation: