Assume that females have pulse rates that are normally distributed with a mean of mu equals 75.0 beats per minute and a standard deviation of sigma equals 12.5 beats per minute. Complete parts (a) through (c) below. a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 78 beats per minute.

0.40517 is the probability

Step-by-step explanation:

The first thing to do here is to calculate the corresponding z-score

Mathematically;

z-score = x-mean/SD

from the question,

x = 78, mean = 75 and SD = 12.5

Plugging these values in the z-score equation, we have;

z-score = (78-75)/12.5 = 3/12.5 = 0.24

So the probability we want to calculate is that;

P(z < 0.24)

we can get this by using the standard normal distribution table,

The value according to the table is;

0.40517

y=mx+b

step-by-step explanation:

m is slope, b is y-intercept

step-by-step explanation: