If it rains, I do not go sailing. It rains 10 % 10\% 10% of days; I go sailing 3 % 3\% 3% of days. If it does not rain, what is the (conditional) probability that I go sailing? Written "p(I go sailing | it does not rain)''

0.03333 or 1/30

Step-by-step explanation:

Let A =" I go sailing" and B = "it does not rain"

P(A) = 0.03

P(B) =0.90

Since I never go sailing when it rains, P(A and B) =0.03.

Therefore, the (conditional) probability that I go sailing, given that it does not rain is:

The probability is 0.03333 or 1/30.

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3