Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5?

The difference is a binomial with a degree of 6

Step-by-step explanation:

Given:

a^3b + 9a^2b^2 − 4ab^5 and a^3b − 3a^2b^2 + ab^5

Let A = a^3b + 9a^2b^2 - 4ab^5

B= a^3b - 3a^2b^2+ab^5

The difference between A and B is

A - B = a^3b + 9a^2b^2 - 4ab^5 - (a^3b - 3a^2b^2 + ab^5)

Open parenthesis

A - B= a^3b + 9a^2b^2 - 4ab^5 - a^3b + 3a^2b^2 - ab^5

= a^3b - a^3b + 9a^2b^2 + 3a^2b^2 - 4ab^5 - ab^5

= 12a^2b^2 - 5ab^5

The fist term 12a^2b^2 has 2+2=4 as a degree

The second term 5ab^5 has 1 +5 =6 as a degree

Therefore,

the answer is: The difference is a binomial with a degree of 6