Which is true about the solution to the system of inequalities shown? y > 3x + 1 y 3x + 1 are solutions. Only values that satisfy y 3x + 1 or y < 3x – 3 are solutions. There are no solutions.

The correct option is;

There are no solutions

Step-by-step explanation:

From the graph of the inequality, with the y-intercept = 1 and slope = 3 for the blue shaded inequality

The equation is y > 3x + 1

While that of the other red shaded inequality, the slope is 3 and the y-intercept = -3

The equation is y < 3x - 3

Given that the two inequalities are parallel line that their domains do not overlap, we have that there are no solutions as the y-coordinate values of  y > 3x + 1 are always larger for a given x-coordinate value than the y-coordinate value of y < 3x - 3.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

-2

7 - 9 = -2

reversed:

-2 + 9 = 7