Write the equation of a line that is perpendicular to y=-2x/7+9 and that passes through the point (4,−6)

  y = (7/2)x -20

Step-by-step explanation:

The given line is in slope-intercept form, so you can read its slope from the equation.

  y = mx + b . . . . . m is the slope; b is the y-intercept

  y = -(2/7)x + 9 . . . . . . has slope -2/7

The perpendicular line will have a slope that is the negative reciprocal of this, so will be ...

  m = -1/(-2/7) = 7/2

We can use this and the given point to write the equation in point-slope form.

  y = m(x -h) +k . . . . . . line with slope m through point (h, k)

We have m = 7/2, (h, k) = (4, -6) so the equation is ...

  y = (7/2)(x -4) -6

  y = (7/2)x -20

answer: no

step-by-step explanation:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.