The useful life of an electrical component is exponentially distributed with a mean of 1000 hours a. What is the probability the circuit will last more than 2000 hours?

0.865

Step-by-step explanation:

To solve for the probability we would be using the formula:

F(x) = 1 - e^−λx

Therefore, P(x > 2000) = F(x) = 1 - e^−λx

Mean = 1000 hours

λ = 1/mean = 1/1000 hours

x= 2000 hours

F(x) = 1 - e^−(1/1000)2000

F(x) = 1 - e^−2

= 0.8646647168

Therefore, the probability the the circuit will last at least 2000 hours = 0.865

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step-by-step explanation:

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step-by-step explanation: