You weigh six packages and find the weights to be 26, 18,58,22,54,and 50 ounces. If you include a package that weighs 66 ounces, which will increase more, the median or the mean?

Step-by-step explanation:

The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given,

Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38

If you include a package that weighs 66 ounces, the new mean would be

New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42

For the median, we would rearrange the weights in ascending order. It becomes

18, 22, 26, 50, 54, 58

Median = (26 + 50)/2 = 38

By adding the new weight, it becomes

18, 22, 26, 50, 54, 58, 66

New median = 50

It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb