PLS HEL 15 POINTS The graph for the equation y = negative 2 x + 1 is shown below. On a coordinate plane, a line with negative slope goes through (0, 1) and (1, negative 1). If another equation is graphed so that the system has no solution, which equation could that be?
Options:
y = negative 2 (x minus one-half)
y = negative one-half (4 x + 2)
y = negative x + 1
y = negative one-half x + 2

y = negative 2 (x minus one-half)

Step-by-step explanation:

The equation of a line is given as:

y = mx + c, where m is the slope and c is the intercept on the y axis.

The equation of a line going through (0, 1) and (1, - 1) is calculated using:

The solution of two lines is at their point of intersection. The equation of the line that would not have any solution with y = -2x + 1 would be a line that is parallel to y = -2x + 1. Since the two lines would be parallel to each other, their would be no intersection and therefore no solution.

Two lines are said to be parallel to each other if they have the same slope. The slope of y = -2x + 1 is gotten by comparing with y = mx + c, therefore the slope m = -2. From the options the only line with a slope m = -2 is y = -2(x -1/2). Therefore y = -2(x -1/2) is parallel to y = -2x + 1 and would have no solution

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

i believe that the answer is

b. y-1=-2(x-4)

hope this !