You have $9000 with which to build a rectangular enclosure with fencing. The fencing material costs $30 per meter. You also want to have two partitions across the width of the enclosure, so that there will be three separated spaces in the enclosure. The material for the partitions costs $25 per meter. What is the maximum area you can achieve for the enclosure

i explained it

Step-by-step explanation:

The total cost of the fence will be 30(2L + 2W) + 2*25 W <= 9000

60L + 110W <= 9000

60 L <= 9000 - 110W

L <= 150 - 11/6 W

For a given width, the maximum area will correspond to the maximum length, so we can just go ahead and say L = 150 - 11/6 W

A = LW = (150 - 11/6 W) W

A = 150 W - 11/6 W2

A' = 150 - 11/3 W = 0

150 = 11/3 W

W = 450/11

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )