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subtract 8 from both sides
![-8y=x-8[\tex] divide both sides by (-8)[tex]\dfrac{-8y}{-8}=\dfrac{x}{-8}-\dfrac{8}{-8}\\\\y=-\dfrac{1}{8}x+1](/tpl/images/0712/3838/b821a.png)
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Find the inverse of the one-to-one function f(x)=-8x+8...
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