If f(x) = -6x + 5 and g(x) = x+1,
what is (fºg)(3)?

(f o g)(3) = -19

Step-by-step explanation:

(f o g)(3) is f(g(3)).  You need to first find g(3).

g(x) = x + 1

g(3) = 3 + 1

g(3) = 4

Next, you need to find f(g(3)).  Since, g(3) = 4, you are finding f(4).

f(x) = -6x + 5

f(4) = -6(4) + 5

f(4) = -24 + 5

f(4) = -19

(f o g)(3) = -19

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: