Which of the following equations describes the graph?

Step-by-step explanation:

the graph is clearly that of a parabola that opens up and has its vertex at (2, -1).  The coefficient of x^2 must be + because the parabola opens up.  

Using the point-slope formula y - k = a(x - h)^2, and letting 2 replace h and -1 replace k, we get:

y + 1 = a(x - 2)^2  or  y = a(x - 2)^2 - 1

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right