An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft.

The distance between the plane and the observer is 16,659.18ft

Step-by-step explanation:

Complete question:

(An observer (O) spots a plane flying at a 42° angle to his horizontal line of sight. If the plane is flying at an altitude of 15,000 ft, what is the distance between the observer and the plane)

Hello,

The question above requires us to find the distance between an observer and a plane. This is very much easy because we are given the angle at which the observer makes with the plane. To solve this question correctly, we need a pictorial representation of the situation.

See attached document for better illustration

In the diagram, we need to find x.

Since the observer and the plane makes a right angled triangle with the distance apart them, we can use SOHCAHTOA

In this case, we have to use Tangent

Tanθ = opposite/ adjacent

θ = 42°

Opposite = 15,000

Adjacent = x

Tan42 = 15000 / x

x = 15000 / tan42

x = 15000 / 0.90

x = 16,659.18ft

The horizontal distance between the observer and the plane is 16,659.18ft

I am not too sure but I know it is not 10,035, or 16,648, nor 20,188 because I put that and it wasn’t right so the last option would be.

22,417

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

idk

step-by-step explanation: