What is the expectation for a binomial distribution with p = 0.5 and n = 8?

4

Step-by-step explanation:

Given the following :

P = probability of success = 0.5

n = number of trials = 8

The expected value of a binomial distribution with probability of success P and number of trials n is defined by:

E(n, p) = n * p

Therefore, expected value when P = 0.5 and n = 8

E(8, 0.5) = 8 × 0.5

= 4

The expected value of the binomial distribution is 4

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y + 11 = (1/4)(x + 16)

step-by-step explanation: