Find the P-value for the indicated hypothesis test. In a sample of 88 children selected randomly from one town, it is found that 8 of them suffer from asthma. Find the P-value for a test of the claim that the proportion of all children in the town who suffer from asthma is equal to 11%. Group of answer choices

0.5686

Step-by-step explanation:

The alternative hypothesis would be p ≠ 0.11. Thus, this is a two tailed test.

We are given;

p = 0.11

p^ = 8/88 = 1/11 = 0.0909

n = 88

Formula for the Test Statistic is given by;

z = (p^ - p)/(√(p(1-p)/n))

z = (0.0909 - 0.11)/(√(0.11(1 - 0.11)/88))

z = - 0.572642

z ≈ -0.57

Now, from the z-table to find the P-value at z = -0.57 is; 0.2843

Since this is a two tailed test, we have to multiply the P-value by 2 to get the total P-value.

Thus, P-value = 2 × 0.2843 = 0.5686

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐