4 solid cubes were made out of the same material. All four have different side lengths: 6cm, 8cm, 10cm, and 12cm. How to distribute the cubes onto two plates of a scale so the scale is balanced? A= the cube with side length 6 cm, B= the cube with side length 8 cm, C= the cube with side length 10 cm, D= the cube with side length 12 cm. On one side of the scale : , on the other side of the scale : Which is the odd one out?

Step-by-step explanation:

4 solids cubes A, B, C and D have been made with the same material.

Since material is same density of the material (grams per cm³) will be same.

It shows that the weight of the cubes will vary in the ratio of their volumes.

Volume of cube A = 6³ = 216 cm³

Volume of cube B = 8³ = 512 cm³

Volume of cube C = 10³ = 1000 cm³

Volume of cube D = 12³ = 1728 cm³

Therefore, weights of these cubes will be in the same proportion.

Since, Volume of D = Volume of (A + B + C)

1728 = (216 + 512 + 1000)

1728 = 1728

Therefore, weights of A, B, C, D will be arranged in the same way to balance the plates of a scale.

On one side of the scale cubes A, B, and C should be placed and on the the other side of the scale cube D should be placed to balance the scale.

answer: c

step-by-step explanation: because you don't have to draw a point of intersection. couldyou give me brainliest?

u

no solution

step-by-step explanation:

there is not enough information in the problem to solve.