A bag contains 1 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the probability both beads drawn are green.
6
~
7

9/16

Step-by-step explanation:

There are 4 beads in the bag, 1 purple and 3 green

P ( green) = green/total

                = 3/4

The bead is replaced

There are 4 beads in the bag, 1 purple and 3 green

P ( green) = green/total

                = 3/4

P ( green, replace, green) =P( green) * P ( green)

                                           = 3/4 * 3/4

                                            = 9 /16

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option