If y varies jointly with x and y =3 when x=2 and z=4 find y when x=8 and z=12

y=10

Step-by-step explanation:

As you can see, the order when x=2 and z=4, is y=x+1, z=y+1, therefore y was 3.

Then, you can find y when x=8 and z=12 by:

12-8=4 (the difference between z and x)

and then divide 4 by 2 (the number of intervals between x, y, and z)

then get 2 (as the difference between x and y.

The answer is 8+2=10.

Hope this helps!

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x