Find the tangent of the angle in between the lines 2x+3y–5=0 and 5x=7y+3?

tanФ = 2.6363636

Step-by-step explanation:

To find the tangent of the angle in-between the lines we will follow the steps below:

We are going to use the formula;

tanФ = |m₂ - m₁  / 1 + m₁m₂|

We can get the slope m₁ from the first equation

2x+3y–5=0

we will re-arrange it in the form y=mx + c

3y = -2x + 5

Divide through by 3

y = -x +

comparing the above equation with y=mx + c

m₁ =  -

We will proceed to find the second slope m₂ using the second equation

5x=7y+3

we will re-arrange it in the form y=mx + c

7y = 5x -3

divide through by 7

y = x -  

comparing the above with y=mx + x

m₂ =

we can now go ahead and substitute into the formula

tanФ = |m₂ - m₁  / 1 + m₁m₂|

tanФ = | -  (- ) / 1 +  (-₁)( )|

tanФ = | +  / 1 -  |

tanФ = | / |

tanФ = | × |

21 will cancel-out 21

tanФ =

tanФ = 2.636363

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

step-by-step explanation:

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