In ΔJKL, solve for x. Please Help! ASAP! 45 points and brianliest! Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle J measures 27 degrees. A) 66.73 B) 74.89 C) 15.44 D) 38.16

A.

Step-by-step explanation:

In this question we are using SohCahToa.

Looking from the side of the 27 degree angle, we have a value for the opposite side, and we are looking for x which is on the hypotenuse side. In this case you use Tan.

So the equation is tan(27)(34/x)

tan(27) is .509 than you have to do 34/.509 to solve for x.

And x is 66.728

i need a picture

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6