Se tiene una pirámide regular cuadrangular cuyas caras laterales forman con la base un angulo que mide 53º y el area de la superficie lateral es 60 ¿cuanto mide la altura?

La altura de la pirámide es de 8.14 unidades.

Step-by-step explanation:

Hay una pirámide cuadrangular regular cuyas caras laterales forman un ángulo que mide 53º con la base y el área de la superficie lateral es 60. ¿Qué altura tiene?

Dado que el área de superficie lateral = 60

Tenemos

Área del triángulo equilátero = (√3 / 4) × a²

 (√3 / 4) × a² = 60

a² = 60 / (√3 / 4) = 80 · √3

a = √ (80 · √3) = 11.77 unidades

La altura inclinada = Altura de la superficie inclinada = a × sin (60) = 11.77 × sin (60)

La altura inclinada = 11.77 × sin (60) = 10.194 unidades

La altura de la pirámide = Altura inclinada × sin (ángulo de caras laterales con la base)

La altura de la pirámide = 10.194 × sin (53) = 8.14 unidades.

La altura de la pirámide = 8.14 unidades.

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer