Solve the system of equations: y=x^2+3x-6 y=2x-6

Solution: {(-1,-8), (0,-6)}

Step-by-step explanation:

y=x^2+3x-6 ............(1)

y=2x-6 ....................(2)

Solution:

by comparison, the right-hand sides of both equations are equal (to y)

x^2+3x-6 = 2x - 6

Transpose and simplify

x^2 -x = 0

x = -1 or x=0

Substitute  x = -1 in (2)

y = 2(-1) -6 = -8  ..............(-1,-8)

substitute x = 0 in (2)

y = 2(0) -6 = -6 ...............(0,-6)

So there are two solutions, corresponding to the intersection of the quadratic and the straight line.

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