A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground. y=-16x^2+266x+102 The amount of time it takes for the rocket to hit the ground is seconds

17 seconds

Step-by-step explanation:

Solution:-

The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

Where,

                   y: The height of the rocket from ground

                   x: The time taken since rocket launch

We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

solve the quadratic equation using quadratic formula as follows:

Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds

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