Find the domain and range of
f(x) = 2sinπx
please help me!
how do I graph this function

Step-by-step explanation:

The general form of a sine wave is:

y = A sin(2π/T x − B) + C

where A is the amplitude,

T is the period,

B is the phase (horizontal shift),

and C is the midline (vertical shift).

f(x) = 2 sin(πx)

This is a sine wave with an amplitude of 2, a period of 2, a phase of 0, and a midline of y=0.

To graph, the wave is centered at y=0 and has zeros every half period (x = 0, 1, 2, 3, etc.).  Between the zeros, the wave is either a min or max (±2).

The domain of the function is (-∞, ∞).

The range of the function is [-2, 2].

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

ian gonna lie that is way to much