HELP PLEASE 5
What is the equation, in point-slope form, of the line
that is perpendicular to the given line and passes
through the point (2,5)?
(2.5)
-2-
(4,2)
O y + 5 = x + 2
Oy- 2 = x-5
Oy-5=-(x-2)
O y + 2 = -(x + 5)
-2 -1.
111.71)
IN

You have the correct answer. Nice work.

Explanation:

The given blue line goes through (1,-1) and (4,2)

Compute the slope of the line through those points using the slope formula

m = (y2 - y1)/(x2 - x1)

m = (2-(-1))/(4 - 1)

m = (2+1)/(4-1)

m = 3/3

m = 1

Apply the negative reciprocal operation to go from a slope of m = 1 to m = -1. Luckily no fractions are involved because the reciprocal of 1 is itself. With any two perpendicular slopes, they always multiply to -1. Keep in mind that neither line can be vertical.

The slope of the perpendicular line is m = -1. It goes through (2,5)

So,

y - y1 = m(x - x1)

y - 5 = -1(x - 2)

y - 5 = -(x - 2)

pointing us to the answer of choice C.