Write the slip-intercept form of the equation of the line described - through: (4,1), parallel to y = 5/6x - 3
- through: (3,3), perp. to y= -3/8x + 2

1) y=⅚x -2⅓

2) y=8/3x -5

Step-by-step explanation:

Point-slope form:

y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient.

Gradient of given line=

Thus, m=⅚

Susbt. m=⅚ into the equation,

y= ⅚x +c

Since the line passes through the point (4, 1), (4, 1) must satisfy the equation. Thus, substitute (4, 1) into the equation to find c.

When x=4, y=1,

1= ⅚(4) +c

Thus the equation of the line is .

The gradients of perpendicular lines= -1.

Gradient of given line= -⅜

-⅜(gradient of line)= -1

gradient of line

= -1 ÷ (-⅜)

= -1 ×(-8/3)

=

When x=3, y=3,

Thus the equation of the line is .