In a circle PQ & RS are two chords bisecting each other, prove that the two parts of one chord are equal to the two parts of the other.

see proof below

Step-by-step explanation:

Let

p1,p2 = half lengths of chord p

q1,q2 = half length of chord q

By the intersecting chord theorem,

p1*p2 = q1*q2,    substituting p1=p2, q1=q2

p1^2 = q1*2

Take square-roots and reject negative roots

p1 = q1

therefore

p1=p2 = q1=q2, or

two parts of one chord are equal to the two parts of the other.

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

answ5

step-by-step explanation:

u have to pay atttion to me