A long-time authorized user of an account makes 0.2 seconds between keystrokes. One day, data are recorded as someone typed the correct username and password. The average time between keystrokes was 0.3 with a standard deviation equal to 0.1183. The sample size was 25. 1. At a 1% level of significance, is this an evidence of an unauthorized attempt? Hint: Use a statistical test.
2. Can you apply the z-test and the normal approximation of the Z test statistic to this set of data? Are the conditions on the data for the test satisfied?

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

b mark me branliest thx

step-by-step explanation: