triangle JKM with side j across from angle J, side k across from angle K, and side m across from angle M If j is 21 inches, k is 12 inches, and ∠M measures 62°, then find m using the Law of Cosines. Round your answer to the nearest tenth. 883 in 348 in 29.7 in 18.7 in

D) 18.7

Step-by-step explanation:

a^2 + b^2 − 2ab*cos(C) = c^2

so j^2+k^2-2jk*cos(M(in radians)) = m^2

441+144-(2*21*12*cos(1.0821)) =m^2

585-(504*cos(1.0821)) = m^2

348.384492 = m^2

sqrt(348.384492) = m

18.6650607 = m

18.7 = m

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: