Find the limit L for the given function f, the point x 0, and the positive number epsilon. Then find a number delta > 0 such that, for all x, 0less thanStartAbsoluteValue x minus x 0 EndAbsoluteValueless thandelta double right arrow StartAbsoluteValue f (x )minus Upper L EndAbsoluteValueless thanepsilon.

L = -25 and  δ = 0.02

Step-by-step explanation:

The function f, point and ε is missing in the question.

The function, f is f(x) = - 4x - 9

           point,   = 4

        epsilon, ε = 0.08

So by the definition of limit,

Therefore,

L= -4(4)-9

L= -16-9

L= -25

So, for every ε > 0, for all δ > 0 such that

|f(x) - L| < ε