A student know that one side of a triangle is 19 cm. Which set of two sides are possible for the lengths of the other two sides of this triangle? 7 cm and 11 cm

8 cm and 8 cm

7 cm and 12 cm

5 cm and 16 cm

D. 5 cm and 16 cm

Step-by-step explanation:

In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.

The sum of the two lengths given must be greater than 19 cm.

A.

7 cm + 11 cm = 18 cm

18 cm < 19 cm

No triangle

B.

8 cm + 8 cm = 16 cm

16 cm < 19 cm

No triangle

C.

7 cm + 12 cm = 19 cm

19 cm = 19 cm

No triangle

D.

5 cm + 16 cm = 21 cm

21 cm > 19 cm

There is a triangle.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

goog may be able to you find that answer