Find the probability of rolling a three first and then a ten when a pair of dice is rolled twice

1/216

Step-by-step explanation:

When a pair of dice is rolled, there are 36 possible different outcomes.

Of those 36 different outcomes, a sum of 3 is obtained in 2 different ways: 1, 2 and 2, 1.

Of those 36 different outcomes, a sum of 10 is possible in 3 different ways: 6, 4; 5, 5; 4, 6.

p(3 followed by 10) = p(3) * p(10) = 2/36 * 3/36 = 1/18 * 1/12 = 1/216

i think the correct option is the second option.