50. At a booth at the school carnival in past years, they've found that 32% of students win a stuffed toy ($3.25), 10% of students win a jumprope ($1.70), and 8% of students win a t-shirt ($7.80). The remaining students do not win a prize. If 200 students play the game at the booth, how much money should the carnival committee expect to pay for prizes for that booth

The expected amount to be paid by the carnival committee for prices would be $366.80

Step-by-step explanation:

Hello!

Here, we want to calculate the amount of money the carnival committee is expected to pay for the prizes for that booth

From the question, we have 3 categories of prices to be won

To calculate for people that won’t win anything , we simply subtract the percentages of all from 100

That would be 100-32-10-8 = 100-50 = 50%

So now let’s calculate the number of people out of 200 that will win each category based on the percentages

For stuffed toy

32/100 * 200 = 64

Jump rope

10/100 * 200 = 20

For t-shirt

8/100 * 200 = 16

So total price paid for stuffed toy= 3.25 * 64 = $208

For jump rope, we have 1.7 * 20 = $34

For t-shirt , we hav 16 * 7.8 = $124.8

So the total value spent on prices by the committee would be;

124.8 + 34 + 208 = $366.80

number one is the correct answer

step-by-step explanation: dogs and cats are mentioned, no other animals

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: