I will mark brainliest i need help quick

x-1

Step-by-step explanation:

| x-1|  x> 1

Since x is greater than x, the absolute value will be positive so we can remove it

x-1

Lets use a number to check

Let x = 4

| 4-1|    4>1

3  which is positive

x - 1

Step-by-step explanation:

| x - 1 |

x > 1

x is greater than 1. The absolute value is not needed, since the value inside will only be for positive integers.

x - 1

We can check by plugging x as 2.

2 - 1 = 1 (positive)

2 > 1

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

£56

step-by-step explanation: