Part of the proceeds from a garage sale was $440 worth of $10 and $20 bills. If there were 2 more $10 bills than $20 bills, find the number of each denomination.

Hey there! I'm happy to help!

Let's set this up a system of equations where x represents the number of 10 dollar bills and y represents the number of 20 dollar bills.

10x+20y=440

x=y+2

We see that x has a value of y+2, so we can replace the x in the first equation with y+2 so we can solve for y.

10(y+2)+20y=440

We use distributive property to undo the parentheses.

10y+20+20y=440

We combine like terms.

30y+20=440

We subtract 20 from both sides.

30y=420

y=14

Since there are 2 more $10 bills, there would be 16 of those.

Therefore, there are 16 $10 bills and 14 $20 bills.

Have a wonderful day! :D

3

step-by-step explanation:

divide 13.5 by 9 to get the scale factor. it equals 1.5

2 * 1.5 = 3