After the first 4 quizzes, Ron’s quiz average is an 87. There are two quizzes remaining for the quarter and the maximum score for any individual quiz is 100. What is the minimum grade Ron can score on one of these two quizzes and still score high enough on the other so that the final quiz average of the six quizzes is at least a 90?

Minimum = 92 ; maximum =100

Step-by-step explanation:

Total number of quizzes = 6

Number of completed quizzes = 4

Number of quizzes left = 2

Average score on completed quizzes = 87

Target average = 90

Maximum score for any individual quiz = 100

Current total score on the 4 quizzes to obtain an average of 87:

87 * 4 = 348

To obtain an average of 90:

Total score must in the six quizzes must be :

90 * 6 = 540

Therefore total score needed in the remaining 2 quizzes to attain an average of 90:

540 - 348 = 192

Since the highest attainable score is 100:

Maximum score Ron can attain on one quiz = 100

Minimum he can attain in the other = 192 - 100 92 in other to score an average of 90 in the six quizzes.

the correct answer is option c.   3

step-by-step explanation:

points to remember

equation of the line with coordinates (x₁, y₁) and (x₂, y₂) is given by,

slope m = (y₂ - y₁)/(x₂ - x₁)

from the figure we can see a line with two coordinates given

to find the slope of given line

here   (x₁, y₁)   = (-1, -1 ) and (x₂, y₂) = (1, 5)

slope m = (y₂ - y₁)/(x₂ - x₁)

  = (5 - -1)/(1 - -1)

  = (5 + 1)/(1 + 1)

  = 6/2 = 3

therefore the correct answer is option c.   3

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: