Zahra wants the equation below to have an infinite number of solutions when the missing number is placed in the box. Box (x minus 3) + 2 x = negative (x minus 5) + 4 Which number should she place in the box?

Below

Step-by-step explanation:

Let y be the missing number inside the box. The equation is:

●y( x-3)+2x= -(x-5)+4

● y (x-3) +2x = -x+5+4

● y (x-3) +2x = -x+9

● y (x-3) +2x+x = 9

●y(x-3)+3x =9

● yx-3y+3x= 9

●yx-3y+3x-9=0

●y(x-3) +3(x-3) =0

● (x-3)(y+3) = 0

●x-3=0 or y+3=0

●x=3 or y = -3

●x=3 or -y = 3

Add them together

● x-y = 6

●x=6+y

● y =6-x

So the number we should put in the box is 6-x