The graph represents function 1 and the equation represents function 2: Function 2 y = 4x + 1

How much more is the rate of change of function 2 than the rate of change of function 1?

Greetings from Brasil...

In a linear function, the rate of change is given by M (see below).

M = rate of change

N = linear coefficient

The Function 2 has M = 4, cause

F(X) = 4X + 1

(M = 4 and N = 1)

For Function 1 we have a rate of change equal to zero, becaus it is a constant function... let's see:

M = ΔY/ΔX

M = (3 - 3)/(4 - 0)

M = 0/4 = 0

So, the Function 2 has 4 times more rate of change than the first

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !