Solve by Cross multiplication method x+2y+1=0 and 2x-3y-12=0

x = 3

y = -2

Step-by-step explanation:

x + 2y + 1 = 0

2x - 3y - 12 = 0

Multiply first equation by -2.

-2x + -4y + -2 = 0

2x - 3y - 12 = 0

Add equations.

0x + -7y - 14 = 0

Solve for y.

-7y = 14

y =-2

Put y as -2 in the first equation and solve for x.

x+2(-2)+1=0

x + -4 + 1 = 0

x = 0 + 4 - 1

x = 3

Step-by-step explanation:

=> -------------------(1)

=> -------------------(2)

Multiplying (1) by 2

=>

=> ------------------(3)

Subtracting (3) from (2)

=>

=> -3y-4y = 14

=> -7y = 14

Dividing both sides by -7

=> y = -2

Now, Put y = -2 in Eq (1)

=> x+2(-2)+1 = 0

=> x -4+1 = 0

=> x - 3= 0

Adding 1 to both sides

=> x = 3

expression #3 is not equivalent. the others are.

answer: i'm great at algebra

~coco

step-by-step explanation: