How does the graph of y = a(x – h)2 + k change if the value of h is doubled? The vertex of the graph moves to a point twice as far from the x-axis. The vertex of the graph moves to a point twice as far from the y-axis. The vertex of the graph moves to a point half as far from the x-axis. The vertex of the graph moves to a point half as far from the y-axis.

Transformation involves changing the position of a function.

When h is doubled in , the vertex of the graph moves to a point twice as far from the y-axis.

The function is given as:

When the value of h is doubled, the new function becomes:

Rewrite as:

The above equation means that:

Function y will be translated to the right by h units

Assume the vertex is:

The new vertex will be:

Comparing the vertices, it means that:

The new function will have its vertex twice as far from the y-axis

Hence, option (b) is correct.

Read more about transformation at:

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The vertex of the graph moves to a point twice as far from the y-axis.

Step-by-step explanation:

How does the graph of y = a(x – h)2 + k change if the value of h is doubled?

The vertex of the graph moves to a point twice as far from the x-axis.

because the role of h is to indicate the distance of the vertex from the y-axis.

The vertex of the graph moves to a point half as far from the x-axis.

The vertex of the graph moves to a point half as far from the y-axis.

step-by-step explanation:

goog be able to you with that maybe

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11