3/x-2, i'm confused as to what the horizontal asymptote is. The resources I found online conclude that it has a horizontal asymptote of y=0. I know that in order for a horizontal asymptote to be y=0, the denominator has to have a greater degree than the numerator. Im confused because doesn't the numerator have the same degree as the denominator (degree of 1)?

The Horizontal Asymptote is at x=3

Step-by-step explanation:

Here is a way to remember this

One way to remember this is the following pnemonic device: BOBO BOTN EATS DC

EABOBO -Exponents are bigger on bottom, y=0

EABOTN -Exponents are bigger on top, none

EATS DC - Exponents are the same, divide coefficients

3/x-2 the exponents are the same, divide leading coefficients

3/1 = 3 the horizontal asymtote is at x=3

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.

answer: -8.2562234e+13