In the lab, Goran has two solutions that contain alcohol and is mixing them with each other. Solution A is 40% alcohol and Solution B is 10% alcohol. He uses 800 milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 30% alcohol solution?

400milliliters

Step-by-step explanation:

Let x=ml of 30% solution B used in resulting mixture.

800+x=ml of resulting 30% solution

40%(800)+10%x=30%(800+x)

Then we can simplify the expression

0.4(800)+0.10x= 0.30(800+x)

320+0.10x=240+0.30x

80=0.20x

x= 400milliliters

Therefore, 400milliliters of 10% solution B used in resulting mixture.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: