Four-digit numerical codes are issued for an ATM. If no integer can be repeated in a code, how many different codes can be formed using only odd integers?

The answer is "120".

Step-by-step explanation:

The assuming numbers:

The  odd number are=

Now we have four places:

In the first place we have 5 option

In second place we have 4 option

In third place, we have 3 option

In fourth place, we have 2 option

So, the value is

So, we have 120 different codes, which form the code.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752