An ancient Greek was born on April 1st, 35 B. C. and died on April 1st, 35 A. D. How many years did he live?

69 years

Step-by-step explanation:

Data provided in the question

Born date of an Ancient Greek = April 1st 35 BC

Diet date of an Ancient Greek = Aril 1st 35 AD

Based on the above information

We can say that

35 + 35 = 70

We deduct 1 as there is no zero

So, it would be

= 70 - 1 year

= 69 years

Hence, An ancient greek lives 69 years and the same is to be considered

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,