You are given 7 to 1 odds against rolling a sum of 6 with the roll of two fair dice, meaning you win $7 if you succeed and you lose $1 if you fail. Find the expected value (to you) of the game.

The expected value of the game is $0.33.

Step-by-step explanation:

There are N = 36 outcomes of rolling two 6-sided fair dice.

The sample for the sum of two numbers to be 7 is:

S = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2) and (6, 1)}

n (S) = 6

It is provided that there is a 7 to 1 odds against rolling a sum of 6 with the roll of two fair dice.

That is, you win $7 if you succeed and you lose $1 if you fail.

Compute the expected value of the game as follows:

Thus, the expected value of the game is $0.33.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

answer: idk

step-by-step explanation: