Set of six numbers has an average of 42. When three of this numbers were removed the remaining three numbers had an average of 72. What was the sum of the removed numbers?

36

Step-by-step explanation:

From the question, we are informed that six numbers has an average of 42. This means that the total number will be equal to:

= 42 × 6

= 252

When three of this numbers were removed the remaining three numbers had an average of 72. The total of this will be:

= 72 × 3

= 216

The sum of the removed numbers will be the difference between the two numbers above. This will be:

= 252 - 216

= 36

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it