Use the ratio of a 30-60-90 triangle to solve for the variables. Make sure to simplify radicals. Leave your answers as radicals in simplest form. u= n=_square root_

A. v = 19√3.

B. u = 38.

Step-by-step explanation:

The following data were obtained from the question:

Angle θ = 60°

Adjacent = 19

Opposite = v

Hypothenus = u

A. Determination of the value of 'v'

The value of v can be obtained by using Tan ratio as shown below:

Angle θ = 60°

Adjacent = 19

Opposite = v

Tan θ = Opposite /Adjacent

Tan 60 = v/19

Cross multiply

v = 19 × Tan 60

Tan 60 = √3

v = 19 × √3

v = 19√3

Therefore, the value of v is 19√3

B. Determination of the value of 'u'

The value of u can be obtained by using cosine ratio as shown below:

Angle θ = 60°

Adjacent = 19

Hypothenus = u

Cos θ = Adjacent /Hypothenus

Cos 60 = 19/u

Cos 60 = 1/2

1/2 = 19/u

Cross multiply

u = 2 × 19

u = 38

Therefore, the value of u is 38.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.