The vertex of the parabola is it 3,-2 when the xvalue is 4 the yvalue is 3 what is the coefficient of the squared term in the parabola equation

5 = a

Step-by-step explanation:

Use the model y - k = a(x - h)^2, where (h, k) represents the vertex.  Here we have:

y + 2 = a(x - 3)^2

Now substitute 4 for x and 3 for y:  

3 + 2 = a(4 - 1)^2, or     5 = a

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form